Use ImageType::Pointer. Here is an example:<div><br></div><div><div>void calc2DJointHistogram(VisualizingImageType::Pointer x, VisualizingImageType::Pointer y, std::string savefilename)</div><div>{</div><div>...</div><div>
}</div><div><br></div><div>//calling it</div><div>VisualizingImageType::Pointer lVis, hVis;</div><div>...</div><div>hVis=hReader->GetOutput();</div><div>calc2DJointHistogram(lVis, hVis, fnNoExt+"_LH.png");</div>
<div><br></div><div>Dženan</div><br><div class="gmail_quote">On Fri, Aug 6, 2010 at 15:32, habibbaluwala2010 <span dir="ltr"><<a href="mailto:habibbaluwala@gmail.com">habibbaluwala@gmail.com</a>></span> wrote:<br><blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex;">
<br>
Hi Everyone,<br>
I am a biot confused on how can i pass an image with smart<br>
pointers to an outside function . I basically need this to avoid reproducing<br>
the code again and again and also to avoid composite filters. It would be<br>
very helpful if you can provide an example which does the job!!! Anyways<br>
looking forward to your replies.<br>
--<br>
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