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I already tried that. Results are different but still not correct...<br>
<br>
On 15/11/2011 10:20, Dženan Zukić wrote:
<blockquote
cite="mid:CAPf2UMSr168tbMsh4p9QLSsk-sdDDiB2FCrdn==cQK2STSSSpw@mail.gmail.com"
type="cite"><font size="2"><font face="verdana,sans-serif">The
order in which you apply rotation and translation is
important. Try the opposite of what you are doing right now.<br>
</font></font><br>
<div class="gmail_quote">2011/11/15 Jeremy Lecoeur <span
dir="ltr"><<a moz-do-not-send="true"
href="mailto:jeremy.lecoeur@vanderbilt.edu">jeremy.lecoeur@vanderbilt.edu</a>></span><br>
<blockquote class="gmail_quote" style="margin: 0pt 0pt 0pt
0.8ex; border-left: 1px solid rgb(204, 204, 204);
padding-left: 1ex;">
<div bgcolor="#ffffff" text="#000000"> So, if I got this
right, my translation should be the difference (in mm)
between the 1st voxel of each image and my rotation should
be based on the three Euler angles. <br>
When I do that, the orientation looks good but not the the
translation. Is there a trick related to the fact that the
two images have different resolutions.<br>
Small volume is 0.0683 x 0.0683 x 0.5 mm and big volume is
0.5 x 0.5 x 0.5 mm.<br>
<br>
Jeremy
<div>
<div class="h5"><br>
<br>
On 11/11/2011 02:39, Dženan Zukić wrote:
<blockquote type="cite"><font size="2"><font
face="verdana,sans-serif">Maybe this example will
help:<br>
<a moz-do-not-send="true"
href="http://www.vtk.org/Wiki/VTK/Examples/Cxx/VolumeRendering/itkVtkImageConvert"
target="_blank">http://www.vtk.org/Wiki/VTK/Examples/Cxx/VolumeRendering/itkVtkImageConvert</a><br>
<br>
</font></font><br>
<div class="gmail_quote">On Thu, Nov 10, 2011 at
21:28, Jeremy Lecoeur <span dir="ltr"><<a
moz-do-not-send="true"
href="mailto:jeremy.lecoeur@vanderbilt.edu"
target="_blank">jeremy.lecoeur@vanderbilt.edu</a>></span>
wrote:<br>
<blockquote class="gmail_quote" style="margin: 0pt
0pt 0pt 0.8ex; border-left: 1px solid rgb(204,
204, 204); padding-left: 1ex;"> <br>
<br>
Hello,<br>
<br>
I have two 3D images, one is a sub-volume of the
other but is not in the<br>
same orientation.<br>
For the big image, I know its size and also the
coordinates in mm of its<br>
first voxel with respect to a frame of reference.<br>
For the small image, I know its size, the
coordinates in mm of its first<br>
voxel with respect to the same frame of reference
and also the 3 euler<br>
angles (phi, theta, psi) that defines its
orientation.<br>
With that, how can I compute the transformation
matrix that will allow<br>
me to see the small image in the big image, at the
right place? I know<br>
it's supposed to be fairly simple but I cannot
figure it out.<br>
<br>
Jeremy<br>
<br>
-- <br>
Jeremy Lecoeur, Ph.D.<br>
<br>
<br>
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<font color="#888888">
<pre cols="72">--
Jeremy Lecoeur, Ph.D.
Research Associate
Vanderbilt University
Phone: <a moz-do-not-send="true" href="tel:%2B1%20615%20343%207798" value="+16153437798" target="_blank">+1 615 343 7798</a>
Fax: <a moz-do-not-send="true" href="tel:%2B1%20615%20343%205459" value="+16153435459" target="_blank">+1 615 343 5459</a></pre>
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<br>
<pre class="moz-signature" cols="72">--
Jeremy Lecoeur, Ph.D.
Research Associate
Vanderbilt University
Phone: +1 615 343 7798
Fax: +1 615 343 5459</pre>
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