[Insight-users] EDM Danielsson filter

Radhika Sivaramakrishna radhika.sivaramakrishna at synarc.com
Mon, 5 Apr 2004 10:02:12 -0700


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Hi,
I am a little confused by the operation of the Danielsson filter. My
understanding of EDM was that at every pixel, I would have the distance from
the nearest background pixel.
 
Also, for pixels within an object, what distances would be returned? I would
like distances to the nearest background pixel, so that I can use this
information for postprocessing.
Is the way it is implemented opposite of that? Does this mean that for
pixels that are part of an object, distance is essentially written out as
zero?
 
Is a simple way to correct that, to just invert the image and then pass it
to the filter?
 
 
Thanks
Radhika
 
                                                     
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<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
style=3D'font-size:10.0pt;
font-family:Arial'>Hi,<o:p></o:p></span></font></p>

<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
style=3D'font-size:10.0pt;
font-family:Arial'>I am a little confused by the operation of the <span
class=3DSpellE>Danielsson</span> filter. My understanding of EDM was =
that at
every pixel, I would have the distance from the nearest background =
pixel.<o:p></o:p></span></font></p>

<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
style=3D'font-size:10.0pt;
font-family:Arial'><o:p>&nbsp;</o:p></span></font></p>

<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
style=3D'font-size:10.0pt;
font-family:Arial'>Also, for pixels within an object, what distances =
would be returned?
I would like distances to the nearest background pixel, so that I can =
use this
information for <span =
class=3DSpellE>postprocessing</span>.<o:p></o:p></span></font></p>

<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
style=3D'font-size:10.0pt;
font-family:Arial'>Is the way it is implemented opposite of that? Does =
this
mean that for pixels that are part of an object, distance is =
essentially
written out as zero?<o:p></o:p></span></font></p>

<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
style=3D'font-size:10.0pt;
font-family:Arial'><o:p>&nbsp;</o:p></span></font></p>

<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
style=3D'font-size:10.0pt;
font-family:Arial'>Is a simple way to correct that, to just invert the =
image
and then pass it to the filter?<o:p></o:p></span></font></p>

<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
style=3D'font-size:10.0pt;
font-family:Arial'><o:p>&nbsp;</o:p></span></font></p>

<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
style=3D'font-size:10.0pt;
font-family:Arial'><o:p>&nbsp;</o:p></span></font></p>

<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
style=3D'font-size:10.0pt;
font-family:Arial'>Thanks<o:p></o:p></span></font></p>

<p class=3DMsoNormal><font size=3D2 face=3DArial><span =
style=3D'font-size:10.0pt;
font-family:Arial'>Radhika<o:p></o:p></span></font></p>

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style=3D'font-size:10.0pt;
font-family:Arial'><span =
style=3D'mso-spacerun:yes'>&nbsp;</span><o:p></o:p></span></font></p>

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<P><FONT SIZE=3D2 FACE=3D"Arial">Confidentiality Notice. </FONT></P>

<P><FONT SIZE=3D2 FACE=3D"Arial">This email message is for the sole use =
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distribution is prohibited. If you are not the intended recipient, =
please contact the sender by reply email and destroy all copies of the =
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that the content of this message is subject to access, review and =
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