[Insight-users] Matrix inversion of a 4x4 transformation matrix
Miller, James V (GE, Research)
millerjv at crd.ge.com
Wed Feb 8 11:59:14 EST 2006
I think you want make the inverse call the other way around
transform->GetInverse(inv);
This will fill "inv" with the inverse of "transform".
Jim
-----Original Message-----
From: insight-users-bounces+millerjv=crd.ge.com at itk.org
[mailto:insight-users-bounces+millerjv=crd.ge.com at itk.org]On Behalf Of
Steffi Meyer
Sent: Wednesday, February 08, 2006 10:33 AM
To: insight-users at itk.org
Subject: [Insight-users] Matrix inversion of a 4x4 transformation matrix
Hi,
I tried this, but as result the identity matrix is returned. Perhaps somewhere is an error.
Can someone help me with this?
const unsigned int Dimension = 4;
typedef itk::AffineTransform<double,Dimension> TransformType;
// Initialize object
TransformType::Pointer transform = TransformType::New();
TransformType::Pointer inv = TransformType::New();
TransformType::Pointer trans = TransformType::New();
// Set up matrix for transform
TransformType::MatrixType matrix;
matrix[0][0] = 5; matrix[0][1] = 0; matrix[0][2] = 5; matrix[0][3] = 0;
matrix[1][0] = 0; matrix[1][1] = 1; matrix[1][2] = 0; matrix[1][3] = 0;
matrix[2][0] = 0; matrix[2][1] = 0; matrix[2][2] = 2; matrix[2][3] = 0;
matrix[3][0] = 0; matrix[3][1] = 0; matrix[3][2] = 0; matrix[3][3] = 1;
transform->SetMatrix(matrix);
cout << transform->GetMatrix() << endl;
inv->GetInverse(transform);
cout << inv->GetMatrix() << endl;
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