[Insight-users] Non-uniform image volumes and BSplineDeformable registration?

[Luis Ibanez]

Hi Motes,

Yes,
the BSpline grid spacings will be different along each direction.


More specifically, they will be:

   BSplineGridSpacingX = (128 - 1)  * imageSpacingX / ( 6 - 1 )
   BSplineGridSpacingY = (150 - 1)  * imageSpacingY / ( 6 - 1 )
   BSplineGridSpacingZ =  ( 40 - 1)  * imageSpacingZ / ( 6 - 1 )


For more details,
you may want to look at the BSplineTransformInitializer class
in:

          Insight/Code/Review/
                  itkBSplineDeformableTransformInitializer.h
                  itkBSplineDeformableTransformInitializer.txx


    Regards,


            Luis

---------------------------------------------------------------------------------
On Wed, Nov 25, 2009 at 11:47 AM, motes motes <mort.motes at gmail.com> wrote:
> Assume that I have a two 3D image volume with the following
> dimensions, 128*150*40. Now I would like to use these volumes as input
> for a BSplineDeformable registration proces with 6 nodes on the image.
>
> Since the volume is not regular will there still be 6 nodes along each
> dimension with different spacing or will there be fewer nodes along
> the "shortest" dimension?
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