[ITK-users] get coordinates of Grid Nodes in Bspline registration

[varasteh]

Dear Matt,

As you kindly guided me, I used the Get* methods to get the followings:
TransformDomainMeshSize = [22, 22, 22]
TransformDomainOrigin = [-246.094, -145.445, -164.5]
TransformDomainPhysicalDimensions = [469.726, 350.586, 280]

For numberOfGridNodesInOneDimension = 25 and SplineOrder = 3, the
TransformDomainMeshSize is [22, 22, 22].

If I am right, the first Node is located at “TransformDomainOrigin”. Now, to
find the locations of other GridNodes I need to have the spacing of Nodes.

1. Is it correct that I just divide “TransformDomainPhysicalDimensions” by
“TransformDomainMeshSize” to get the Nodes spacing or I should divide to 25
(numberOfGridNodes) or is there other method to get Nodes spacing?

2. Sorry, in ITK user guide, I tried to find the definition of SplineOrder
and exactly what is it but I could not understand it! Could you please tell
me what is SplineOrder doing!?

3. I am a bit confused, since the NumberOfParameters = 46875 (= 3x25x25x25)
is exactly correspond to 25 GridNodes, what does it mean! Do I have a
lattice of 25x25x25 GridNodes with MeshSize of [22, 22, 22]??!! 

Many thanks in advance,
             varasteh
_____________________________________
More info about Lung CT and ROI which I am using:
Image Spacing (mm) = [0.976562, 0.976562, 2]
Image Size (pixel) = ImageRegion (0x310fdc8)
  Dimension: 3
  Index: [0, 0, 0]
  Size: [512, 512, 141]
Image Physical Dimension (mm) = [500, 500, 282]
ROI Size (pixel)  = ImageRegion (0x3255278)
  Dimension: 3
  Index: [0, 0, 0]
  Size: [482, 360, 141]
ROI Physical Dimension (mm) = [470.703, 351.562, 282]
Fixed Physical Dimension (mm) = [469.726, 350.586, 280]
numberOfGridNodesInOneDimension = 25
NumberOfIntialParameters = 46875
TransformDomainDirection =  1 0 0 0 1 0 0 0 1
TransformDomainMeshSize = [22, 22, 22]
TransformDomainOrigin = [-246.094, -145.445, -164.5]
TransformDomainPhysicalDimensions = [469.726, 350.586, 280]





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