[Insight-users] itkImageSource for block of memory

[Daniel Blezek]

Hi,

  Allocate will check that the memory size you gave it is correct and will
use the block.  If it is different, it will ignore what you gave it and
allocate a block.

-dan


On 6/26/09 9:11 AM, "Koen Vermeer" <koen at vermeer.tv> wrote:

> On Fri, 2009-06-19 at 08:38 -0500, Daniel Blezek wrote:
>> On 6/19/09 6:38 AM, "Koen Vermeer" <koen at vermeer.tv> wrote:
>>> Cool! What about the other way around, like itkExportImageFilter? It
>>> seems that I cannot find it, but maybe something similar exists with a
>>> different name?
>> We do exactly the same thing as you, i.e. use ITK from a different
>> application.  For the output, to avoid duplicating memory, we do something
>> like this:
>> // Allocate output ImageBuffer
>> ImageBuffer = new T[NumberOfPixels];
>> itkImage = filter->GetOutput()
>> itkImage->GetPixelContainer()->SetImportPointer ( (T*)ImageBuffer,
>>     NumberOfPixels, false );
>> itkImage->Allocate();
>> This creates the buffer, and asks ITK to use it.
> 
> Thanks for your reply! It's almost clear... What I'm wondering is this:
> ImageBuffer is already allocated by 'new'. What does the
> itkImage->Allocate() do in that case? Will it allocate the memory again?
> Or will it just set some internal flag in itkImage to tell that the
> memory is allocated in some other way?
> 
> Best,
> Koen
> 
> 

-- 
Daniel Blezek, PhD
Medical Imaging Informatics Innovation Center

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