[Insight-users] Extract Image Filter

[Dan Mueller]

Hi Gita,

The center point is the position you want to be in the middle of the
resultant image. The "up" vector is simply a vector used to create the
orthogonal frame of reference (given the direction vector and the "up"
vector, you can derive the third orthogonal vector using the cross
product). Therefore the "up" vector can be any arbitrary vector you
desire (so long as it is not the same as the direction vector). The
"up" vector determines the orientation of the resultant 2D image.

Did you run the tests can came with the paper? The following test will
probably be of special interest, as it extracts a cross section of a
synthetic vessel (see Testing/CMakeLists.txt at 107):

ADD_TEST(
    Synthetic_01_Section_Tube
    ${SOURCE_TEST_DRIVER}
    Test_LookAt_ObliqueSection
    ${TESTING_OUTPUT_PATH}/Synthetic-01-Section-Tube.mhd
    ${DATA_PATH}/Synthetic-01.mhd
    14 65 37 0 4 -1 0 1 0
)

I have attached a MIP of the synthetic tube (the red cross is the
center point). The "up" vector was chosen arbitrarily. The direction
vector roughly corresponds to the direction of the tube/vessel.

Hope this helps.

Cheers, Dan

2009/9/23 Gita Das <das_gita at hotmail.com>:
> Hi Dan,
> Thank you for your response.
> I was trying with your code and wanted to get a feel about it. I am a bit
> unsure about the "up" vector.
> In my case I want to get a slice of a segmented vessel that is highly
> tortuous. If it's straight then a slice parallel to Z-axis is fine. But with
> tortuosity I need the slice that is perpendicular to the flow axis . So, I
> can define the "direction to look at" as the direction of flow axis.
> Let's say I want to get the slice as in Fig 1(b) with direction 0,0,-1, as
> described in your Insight article. What was the values given for center
> point and up vector?
> Thank you.
> Regards,
> Gita
>
>
>
>
>> Date: Fri, 18 Sep 2009 17:34:41 +0200
>> Subject: Re: [Insight-users] Extract Image Filter
>> From: dan.muel at gmail.com
>> To: das_gita at hotmail.com
>> CC: insight-users at itk.org
>>
>> Hi Gita,
>>
>> The following Insight Journal article may prove helpful:
>> http://www.insight-journal.org/browse/publication/168
>>
>> Make sure you leave a review :P
>>
>> Cheers, Dan
>>
>> 2009/9/18 Gita Das <das_gita at hotmail.com>:
>> > Hallo,
>> >
>> > I would like to take a slice of 3D image at a plane not parallel to
>> > z-plane
>> > but at an angle say, 45deg to z-plane.
>> > How do I define that?
>> > Any help would be greatly appreciated.
>> > Gita Das
>> >
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