[ITK-users] Inverse gradient

[Pol Monsó Purtí]

Hello all,

Is there a filter to compute

1 / (1 + gradient^p) ?

As in Eq. 17 of http://www.dtic.upf.edu/~vcaselles/papers_v/GAC_article.pdf

If not, a better way than doing it pixel by pixel?

If there isn't I would write a filter myself but I'm really clogged with
work this month :S

Cheers,

Pol
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