[Insight-users] Compute the overlapping volume of two images (by SimilarityIndexImageFilter)

Xabier Artaechevarria Artieda xabiarta at unav.es
Mon Nov 12 05:57:57 EST 2007


Hi Michael,
if I understood right, you want to see the overlap between two images  
of the same size. In that case you can use SimilarityIndexImageFilter  
directly.
Regards,
Xabi

-- 
Xabier Artaechevarria
Cancer Imaging Laboratory
Centre for Applied Medical Research
www.cima.es



Michael Schildt <michael.schildt at ifn-magdeburg.de> ha escrito:

> Hello Xabier!
>
> I try to explain it with other words. I acquired two anatomical data
> sets within one MRI session (3 slices, 256x256 inplane, 4 mm slices
> thickness) with identical parameter. They contain exactly the same
> volume of the brain. Within ITK I do a rigid registration to a third
> high resolution 3D volume (from another scanner) for each of the two
> data sets. (All 3 data sets are T1 weighted.)
>
> I expect for a perfect registration, that the slice data sets are
> positioned exactly at the same position and orientation. To test this,
> i would like to compute this overlap. Until now, i do this by computing
> the euklidian distance of the image centers and the squared differences
> in rotation angles. But the overlap includes both errors and scales
> from 0.0 to 1.0.
>
> Does it help clearifying my issue?
>
> Greetings,
>    Michael
>
> Xabier Artaechevarria Artieda schrieb:
>> Hi Michael,
>> well, this filter is thought to evaluate differente methods to   
>> segment the "same object in the same image". Usually, you want to   
>> see how similar is the volume segmented by method A to the gold   
>> standard. In that context, the inputs to the filter are 2 binary   
>> images of the same size. The regions of interest (on which the   
>> filter works) are also the same.
>> I must say I do not really understand what you are looking for. But  
>>  from your implementation idea, wouldn't it be enough to resize one  
>>  of the images to fit the size of the other? If you explain your   
>> problem in more detail I might give you some other idea.
>>
>> Grüsse,
>> Xabi
>>



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